Apply a function to multiple list or vector arguments Description. Free 30 Day Trial These variables contain times eg. # [[2]] Free 30 Day Trial # [1] 3 11 12 13 # [[3]] # "1 4" "2 5" "3 6" # [1] 2 4 5 6 # # [[2]] it loops over a list, iterating over each element in that list; it applies a function to each element of the list (a function that you specify); and returns a list (the l is for “list”). # [1] 3 6 vf <- Vectorize(f, SIMPLIFY = FALSE) f(1:3,4:6) MARGIN argument is not required here, the specified function is applicable only through columns. # [[1]] mapply applies FUN to the first elements of each ... argument, the second elements, the third elements, and so on. But, I think Tushar wants to return length(x) and nrow(y) both@vasanthcullen I am expecting it to print the values 7, nrow(someDataFrame) two times, since testList has two vectors. Take a brief sojourn into the world of overloaded functions and R’s S3 object system. Watch a video of this section. # Can we use lapply to run testFunc on testList$a and testList$b with same value of y?But I am always getting the length of someDataFrame as the output. I should have used print, to print the number of rows. Here is an example of Use lapply with additional arguments: In the video, the triple() function was transformed to the multiply() function to allow for a more generic approach. Thomas thanks for that too - I hadn't seen that question in my search.Thanks Karl - that should do the trick. lapply() can be used for other objects like data frames and lists. f <- function(x=1:3, y=4:6) c(x,y) Only arguments explicitly passed to this function are evaluated and passed to mapply. # [1] 1 11 12 13 Recursively apply lapply in R. 2. # [1] 42 Usage mapply(FUN, ..., MoreArgs = NULL, SIMPLIFY = TRUE, USE.NAMES = TRUE) Arguments mapply(paste, 1:2, MoreArgs=list(3:4)) # [1] 42 42 # apply FUN to corresponding elements of a list and a vector mapply(paste, 1:2, 3:4, MoreArgs=list(sep='-'), SIMPLIFY=FALSE) # [1] 2 5 # lapply(X, FUN) Arguments: -X: A vector or an object -FUN: Function applied to each element of x l in lapply() stands for list. # [1,] 1 3 5 vf2 <- Vectorize(f, "x", SIMPLIFY = FALSE) # [1] 1 4 # 1. lapply columns of dataframe. By using our site, you acknowledge that you have read and understand our User defined functions Am I missing something obvious.By default, a R function returns the last evaluated valueThanks for contributing an answer to Stack Overflow! rr <- function(x=42, times=1) rep.int(x,times=times) # [[1]]
# [1] "1-3" vf2(1:3,11:13) # [,1] [,2] All it gives me is 7 and nrow(someDataFrame) once. # Hot Network Questions Consequences of Overstaying visa in Taiwan The Overflow Blog
1. lapply columns of dataframe. Refer to the below table … Can we use lapply to run testFunc on testList$a and testList$b with same value of y?But I am always getting the length of someDataFrame as the output. site design / logo © 2020 Stack Exchange Inc; user contributions licensed under I think the point you made regarding R printing the last evaluated value was the reason. # aa bb cc Thus, if an argument with a default is specified by vectorize.args, it is "vectorized" only if it is explicitly passed to the function. How to use lapply and paste on multiple dataframes in a list. I think the point you made regarding R printing the last evaluated value was the reason.
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